49ers land Alexander on 4-year, $54M deal

Tanya Simon
March 12, 2019

The 49ers added a talented piece to their defense, agreeing to terms on a four-year contract with linebacker Kwon Alexander, according to Ian Rapoport of NFL Network.

The 49ers were in the market for a linebacker, and they made a decision to break the bank.

A versatile linebacker, Alexander started all 46 games of his four-year career with the Tampa Bay Buccaneers, although he missed the final 10 games last season with an ACL tear.

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The deal includes $27 million in guaranteed money, a source told ESPN's Adam Schefter. For now, Alexander becomes the highest-paid off-ball linebacker in the NFL. Since this is the "legal tampering" window, the contract can be signed and finalized on Wednesday.

A knee injury that ended Kwon Alexander's season in Week 7 didn't affect his market value. But Alexander also led the National Football League with 67 missed tackles from 2015-17, according to SportRadar.

In three-plus seasons, the former fourth-round pick out of LSU has accumulated six interceptions, six forced fumbles, seven sacks and a touchdown.

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